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QJEEM24Ph0f9c: JEE Main 2024 Physics - Class 11 JEEM24Ph0f9c Solution: The fundamental frequency of a closed organ pipe is equal to…

The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60 cm60 \mathrm{~cm} , the length of the closed pipe will be:

Multiple Choice Options

  • A 15 cm
  • B 60 cm
  • C 45 cm
  • D 30 cm

Step-by-Step Verified Solution

JEE Main 2024 (Online) 31st January Morning Shift Physics - Waves Question 10 English Explanation

amp;f1=v4 L1amp;f1=f2amp;v4 L1=vL2amp;⇒L2=4 L1amp;60=4×L1amp; L1=15 cm\begin{aligned}& \mathrm{f}_1=\frac{\mathrm{v}}{4 \mathrm{~L}_1} \\& \mathrm{f}_1=\mathrm{f}_2 \\& \frac{\mathrm{v}}{4 \mathrm{~L}_1}=\frac{\mathrm{v}}{\mathrm{L}_2} \\& \Rightarrow \mathrm{L}_2=4 \mathrm{~L}_1 \\& 60=4 \times \mathrm{L}_1 \\& \mathrm{~L}_1=15 \mathrm{~cm}\end{aligned}

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