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QJEEM24Ph0f00: JEE Main 2024 Physics - Class 11 JEEM24Ph0f00 Solution: A ball suspended by a thread swings in a vertical plane so that …

A ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle (θ) of thread deflection in the extreme position will be :

Multiple Choice Options

  • A tan−1⁡(12)
  • B 2tan−1⁡(12)
  • C 2tan−1⁡(15)
  • D tan−1⁡(2)

Step-by-Step Verified Solution

JEE Main 2024 (Online) 27th January Evening Shift Physics - Work Power & Energy Question 28 English Explanation

Loss in kinetic energy == Gain in potential energy

⇒12mv2=mgℓ(1−cos⁡θ)⇒v2ℓ=2 g(1−cos⁡θ)

Acceleration at lowest point =v2ℓ

Acceleration at extreme point =gsin⁡θ

 Hence, v2ℓ=gsin⁡θ∴sin⁡θ=2(1−cos⁡θ)⇒tan⁡θ2=12⇒θ=2tan−1⁡(12)

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