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QJEEM24Ph02ce: JEE Main 2024 Physics - Class 12 JEEM24Ph02ce Solution: Three capacitors of capacitances 25 μ F , 30 μ F and 45 μ F are …

Three capacitors of capacitances 25μF,30μF and 45μF are connected in parallel to a supply of 100 V. Energy stored in the above combination is E. When these capacitors are connected in series to the same supply, the stored energy is 9xE. The value of x is _________.

Step-by-Step Verified Solution

E=12(25+30+45)(100)2.... (i)

 Also, 9xE=121(125+130+145)(100)2.... (ii)

From (i) and (ii)

x=86

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