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QJEEM24Mafca1: JEE Main 2024 Mathematics - Class 11 JEEM24Mafca1 Solution: If the Coefficient of in the expansion of is , then equals…

If the Coefficient of x30x^{30} in the expansion of (1+1x)6(1+x2)7(1−x3)8;x≠0\left(1+\frac{1}{x}\right)^6\left(1+x^2\right)^7\left(1-x^3\right)^8 ; x \neq 0 is α\alpha , then ∣α∣|\alpha| equals ___________.

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amp; Coefficient of x30 in (1+x)6(1+x2)7(1−x3)8x6amp;⇒ Coefficient of x36 in (1+x)6(1+x2)7(1−x3)8amp;⇒ General term =6Cr17Cr28Cr3(−1)r3xr1+2r2+3r3amp;⇒r1+2r2+3r3=36\begin{aligned} & \text { Coefficient of } x^{30} \text { in } \frac{(1+x)^6\left(1+x^2\right)^7\left(1-x^3\right)^8}{x^6} \\\\ & \Rightarrow \text { Coefficient of } x^{36} \text { in }(1+x)^6\left(1+x^2\right)^7\left(1-x^3\right)^8 \\\\ & \Rightarrow \text { General term }={ }^6 C_{r_1}{ }^7 C_{r_2}{ }^8 C_{r_3}(-1)^{r_3} x^{r_1+2 r_2+3 r_3} \\\\ & \Rightarrow r_1+2 r_2+3 r_3=36\end{aligned}

 Case-I : r1amp;r2amp;r30amp;6amp;82amp;5amp;84amp;4amp;86amp;3amp;8\text { Case-I : } \begin{array}{|c|c|c|}\hline \mathrm{r}_1 & \mathrm{r}_2 & \mathrm{r}_3 \\\hline 0 & 6 & 8 \\\hline 2 & 5 & 8 \\\hline 4 & 4 & 8 \\\hline 6 & 3 & 8 \\\hline\end{array}

r1+2r2=12(r_1+2 r_2=12 \quad\left(\right. Taking r3=8)\left.r_3=8\right)

amp; Case-II :amp;r1amp;r2amp;r31amp;7amp;73amp;6amp;75amp;5amp;7\begin{aligned}&\text { Case-II :}\\\\&\begin{array}{|l|l|l|}\hline r_1 & r_2 & r_3 \\\hline 1 & 7 & 7 \\\hline 3 & 6 & 7 \\\hline 5 & 5 & 7 \\\hline\end{array}\end{aligned}

r1+2r2=15(r_1+2 r_2=15\left(\right. Taking r3=7)\left.r_3=7\right)

amp; Case-III : amp;r1amp;r2amp;r34amp;7amp;66amp;6amp;6\begin{aligned}&\text { Case-III : }\\\\&\begin{array}{|l|l|l|}\hline r_1 & r_2 & r_3 \\\hline 4 & 7 & 6 \\\hline 6 & 6 & 6 \\\hline\end{array}\end{aligned}

amp; Coefficient=7+(15×21)+(15×35)+(35)amp;−(6×8)−(20×7×8)−(6×21×8)+(15×28)amp;+(7×28)=−678=αamp;∣α∣=678\begin{aligned} & \text { Coefficient}=7+(15 \times 21)+(15 \times 35)+(35) \\\\ & -(6 \times 8)-(20 \times 7 \times 8)-(6 \times 21 \times 8)+(15 \times 28) \\\\ & +(7 \times 28)=-678=\alpha \\\\ & |\alpha|=678\end{aligned}

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