Verified Solution • 2025–26 Session moderate

QJEEM24Maf3a9: JEE Main 2024 Mathematics - Class 11 JEEM24Maf3a9 Solution: If is the solution of , then the value of is

If \alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2} is the solution of 4cos⁡θ+5sin⁡θ=14 \cos \theta+5 \sin \theta=1 , then the value of tan⁡α\tan \alpha is

Multiple Choice Options

  • A 10−1012\frac{10-\sqrt{10}}{12}
  • B 10−106\frac{\sqrt{10}-10}{6}
  • C 10−1012\frac{\sqrt{10}-10}{12}
  • D 10−106\frac{10-\sqrt{10}}{6}

Step-by-Step Verified Solution

4+5tan⁡θ=sec⁡θ4+5 \tan \theta=\sec \theta

Squaring : 24tan⁡2θ+40tan⁡θ+15=024 \tan ^2 \theta+40 \tan \theta+15=0

tan⁡θ=−10±1012\tan \theta=\frac{-10 \pm \sqrt{10}}{12}

and tan⁡θ=−(10+1012)\tan \theta=-\left(\frac{10+\sqrt{10}}{12}\right) is Rejected.

(3) is correct.

Related Learning Resources & Exam Preparation