QJEEM24Maf1c1: JEE Main 2024 Mathematics - Class 12 JEEM24Maf1c1 Solution: If an unbiased dice is rolled thrice, then the probability of…

Let's denote the outcomes of the three rolls as $X_1$ , $X_2$ , and $X_3$ , where $X_i$ represents the number obtained in the $i^{\text{th}}$ roll. We are looking for the probability that:

X_2 > X_1 \text{ and } X_3 > X_2

The total number of outcomes when rolling a dice three times is:

$6^3 = 216$

Let's count the favorable outcomes. For each satisfying outcome, we must ensure that both inequalities are adhered to. Consider the possible sequences where every subsequent roll's number is higher than the previous roll's number. These sequences are:

• (1, 2, 3)
• (1, 2, 4)
• (1, 2, 5)
• (1, 2, 6)
• (1, 3, 4)
• (1, 3, 5)
• (1, 3, 6)
• (1, 4, 5)
• (1, 4, 6)
• (1, 5, 6)
• (2, 3, 4)
• (2, 3, 5)
• (2, 3, 6)
• (2, 4, 5)
• (2, 4, 6)
• (2, 5, 6)
• (3, 4, 5)
• (3, 4, 6)
• (3, 5, 6)
• (4, 5, 6)

Clearly, there are 20 such favorable outcomes. Hence, the probability is given by:

$\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{20}{216} = \frac{5}{54}$

Therefore, the correct option is:

Option A: $\frac{5}{54}$