Verified Solution • 2025–26 Session moderate

QJEEM24Macc7b: JEE Main 2024 Mathematics - Class 11 JEEM24Macc7b Solution: Let α , β be the distinct roots of the equation x 2 − ( t 2 − 5 …

Let α,β be the distinct roots of the equation x2−(t2−5t+6)x+1=0,t∈R and an=αn+βn. Then the minimum value of a2023+a2025a2024 is

Multiple Choice Options

  • A −1/2
  • B −1/4
  • C `1/4
  • D `1/2

Step-by-Step Verified Solution

x2−(t2−5t+6)x+1=0∴a2025−(t2−5t+6)a2024+a2023=0⇒a2025+a2023a2024=t2−5t+6=(t+52)2+(−14) Minimum value =−14

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