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QJEEM24Maaf59: JEE Main 2024 Mathematics - Class 11 JEEM24Maaf59 Solution: The number of solutions of , where , is ________.

The number of solutions of sin⁡2x+(2+2x−x2)sin⁡x−3(x−1)2=0\sin ^2 x+\left(2+2 x-x^2\right) \sin x-3(x-1)^2=0 , where −π≤x≤π-\pi \leq x \leq \pi , is ________.

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amp;sin⁡2x+(3−(x−1)2)sin⁡x−3(x−1)2=0amp;sin⁡2x+3sin⁡x−(x−1)2sin⁡x−3(x−1)2=0amp;sin⁡x(sin⁡x+3)−(x−1)2)[sin⁡x+3]=0\begin{aligned}& \sin ^2 x+\left(3-(x-1)^2\right) \sin x-3(x-1)^2=0 \\& \sin ^2 x+3 \sin x-(x-1)^2 \sin x-3(x-1)^2=0 \\& \left.\sin x(\sin x+3)-(x-1)^2\right)[\sin x+3]=0\end{aligned}

JEE Main 2024 (Online) 5th April Evening Shift Mathematics - Trigonometric Equations Question 2 English Explanation

There are two intersections between this graph.

So, Number of solution will be 2 .

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