Verified Solution • 2025–26 Session moderate

QJEEM24Maa4ab: JEE Main 2024 Mathematics - Class 12 JEEM24Maa4ab Solution: If , then at is equal to

If log⁡ey=3sin⁡−1x\log _e y=3 \sin ^{-1} x , then (1−x2)y′′−xy′(1-x^2) y^{\prime \prime}-x y^{\prime} at x=12x=\frac{1}{2} is equal to

Multiple Choice Options

  • A 9eπ/29 e^{\pi / 2}
  • B 9eπ/69 e^{\pi / 6}
  • C 3eπ/23 e^{\pi / 2}
  • D 3eπ/63 e^{\pi / 6}

Step-by-Step Verified Solution

amp;log⁡ey=3sin⁡−1xamp;amp;y=e3sin⁡−1xamp;dydx=e3sin⁡−1x⋅31−x2\begin{aligned}&\log _e y=3 \sin ^{-1} x\\&\begin{aligned}& y=e^{3 \sin ^{-1} x} \\& \frac{d y}{d x}=e^{3 \sin ^{-1} x} \cdot \frac{3}{\sqrt{1-x^2}}\end{aligned}\end{aligned}

1−x2dydx=3y\sqrt{1-x^2} \frac{d y}{d x}=3 y

Again differentiate

amp;1−x2⋅y′′−2x21−x2y′=3y′amp;(1−x)2y′′−xy′=3y′(1−x2)\begin{aligned}& \sqrt{1-x^2} \cdot y^{\prime \prime}-\frac{2 x}{2 \sqrt{1-x^2}} y^{\prime}=3 y^{\prime} \\& (1-x)^2 y^{\prime \prime}-x y^{\prime}=3 y^{\prime}\left(\sqrt{1-x^2}\right)\end{aligned}

So value of 3y′(1−x2)3 y^{\prime}\left(\sqrt{1-x^2}\right) at x=12x=\frac{1}{2}

amp;3⋅31−x2esin⁡−1x(1−x2)amp;=9e3π6=9eπ2\begin{aligned}& 3 \cdot \frac{3}{\sqrt{1-x^2}} e^{\sin ^{-1} x}\left(\sqrt{1-x^2}\right) \\& =9 e^{3 \frac{\pi}{6}}=9 e^{\frac{\pi}{2}}\end{aligned}

Related Learning Resources & Exam Preparation