Verified Solution • 2025–26 Session moderate QJEEM24Maa4ab: JEE Main 2024 Mathematics - Class 12 JEEM24Maa4ab Solution: If , then at is equal to If logey=3sin−1x\log _e y=3 \sin ^{-1} xlogey=3sin−1x , then (1−x2)y′′−xy′(1-x^2) y^{\prime \prime}-x y^{\prime}(1−x2)y′′−xy′ at x=12x=\frac{1}{2}x=21 is equal to Multiple Choice Options A 9eπ/29 e^{\pi / 2}9eπ/2 B 9eπ/69 e^{\pi / 6}9eπ/6 C 3eπ/23 e^{\pi / 2}3eπ/2 D 3eπ/63 e^{\pi / 6}3eπ/6 Step-by-Step Verified Solution amp;logey=3sin−1xamp;amp;y=e3sin−1xamp;dydx=e3sin−1x⋅31−x2\begin{aligned}&\log _e y=3 \sin ^{-1} x\\&\begin{aligned}& y=e^{3 \sin ^{-1} x} \\& \frac{d y}{d x}=e^{3 \sin ^{-1} x} \cdot \frac{3}{\sqrt{1-x^2}}\end{aligned}\end{aligned}amp;logey=3sin−1xamp;amp;y=e3sin−1xamp;dxdy=e3sin−1x⋅1−x23 1−x2dydx=3y\sqrt{1-x^2} \frac{d y}{d x}=3 y1−x2dxdy=3y Again differentiate amp;1−x2⋅y′′−2x21−x2y′=3y′amp;(1−x)2y′′−xy′=3y′(1−x2)\begin{aligned}& \sqrt{1-x^2} \cdot y^{\prime \prime}-\frac{2 x}{2 \sqrt{1-x^2}} y^{\prime}=3 y^{\prime} \\& (1-x)^2 y^{\prime \prime}-x y^{\prime}=3 y^{\prime}\left(\sqrt{1-x^2}\right)\end{aligned}amp;1−x2⋅y′′−21−x22xy′=3y′amp;(1−x)2y′′−xy′=3y′(1−x2) So value of 3y′(1−x2)3 y^{\prime}\left(\sqrt{1-x^2}\right)3y′(1−x2) at x=12x=\frac{1}{2}x=21 amp;3⋅31−x2esin−1x(1−x2)amp;=9e3π6=9eπ2\begin{aligned}& 3 \cdot \frac{3}{\sqrt{1-x^2}} e^{\sin ^{-1} x}\left(\sqrt{1-x^2}\right) \\& =9 e^{3 \frac{\pi}{6}}=9 e^{\frac{\pi}{2}}\end{aligned}amp;3⋅1−x23esin−1x(1−x2)amp;=9e36π=9e2π Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring