In a triangle ABC,BC=7,AC=8,AB=α∈N and cosA=32 . If 49cos(3C)+42=nm , where gcd(m,n)=1 , then m+n is equal to _________.
Step-by-Step Verified Solution

amp;cosA=32=2⋅α⋅8α2+82−72amp;⇒(α2+15)3=32αamp;3α2−32α+45=0amp;⇒α=35,9amp;∵α∈N⇒α=9amp;cosC=2⋅7⋅872+82−92=72
cos3C=49cos3C⇒⇒amp;=4cos3C−3cosCamp;734×8−76amp;=732−42amp;49cos3C+42=732amp;m+n=39