Verified Solution • 2025–26 Session moderate QJEEM24Ma9758: JEE Main 2024 Mathematics - Class 12 JEEM24Ma9758 Solution: If ∫ π 6 π 3 1 − sin 2 x d x = α + β 2 + γ 3 , where α , β… If ∫π6π31−sin2xdx=α+β2+γ3, where α,β and γ are rational numbers, then 3α+4β−γ is equal to _________. Step-by-Step Verified Solution =∫π6π31−sin2xdx=∫π6π3|sinx−cosx|dx=∫π6π4(cosx−sinx)dx+∫π4π3(sinx−cosx)dx=−1+22−3=α+β2+γ3α=−1,β=2,γ=−13α+4β−γ=6 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring