Verified Solution • 2025–26 Session moderate

QJEEM24Ma9758: JEE Main 2024 Mathematics - Class 12 JEEM24Ma9758 Solution: If ∫ π 6 π 3 1 − sin ⁡ 2 x d x = α + β 2 + γ 3 , where α , β…

If ∫π6π31−sin⁡2xdx=α+β2+γ3, where α,β and γ are rational numbers, then 3α+4β−γ is equal to _________.

Step-by-Step Verified Solution

=∫π6π31−sin⁡2xdx=∫π6π3|sin⁡x−cos⁡x|dx=∫π6π4(cos⁡x−sin⁡x)dx+∫π4π3(sin⁡x−cos⁡x)dx=−1+22−3=α+β2+γ3α=−1,β=2,γ=−13α+4β−γ=6

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