Verified Solution • 2025–26 Session moderate QJEEM24Ma9731: JEE Main 2024 Mathematics - Class 11 JEEM24Ma9731 Solution: If are in an A.P. and a are also in an A.P, then is equal to If logea,loge b,logec\log _e \mathrm{a}, \log _e \mathrm{~b}, \log _e \mathrm{c}logea,loge b,logec are in an A.P. and logea−loge2 b,loge2 b−loge3c,loge3c−loge\log _e \mathrm{a}-\log _e 2 \mathrm{~b}, \log _e 2 \mathrm{~b}-\log _e 3 \mathrm{c}, \log _e 3 \mathrm{c} -\log _elogea−loge2 b,loge2 b−loge3c,loge3c−loge a are also in an A.P, then a:b:ca: b: ca:b:c is equal to Multiple Choice Options A 6:3:26: 3: 26:3:2 B 9:6:49: 6: 49:6:4 C 25:10:425: 10: 425:10:4 D 16:4:116: 4: 116:4:1 Step-by-Step Verified Solution logea,logeb,logec\log _{\mathrm{e}} \mathrm{a}, \log _{\mathrm{e}} \mathrm{b}, \log _{\mathrm{e}} \mathrm{c}logea,logeb,logec are in A.P. ∴b2=ac\therefore \mathrm{b}^2=\mathrm{ac}∴b2=ac ..... (i) Also amp;loge(a2b),loge(2b3c),loge(3ca) are in A.P. amp;(2b3c)2=a2b×3caamp;bc=32\begin{aligned}& \log _e\left(\frac{a}{2 b}\right), \log _e\left(\frac{2 b}{3 c}\right), \log _e\left(\frac{3 c}{a}\right) \text { are in A.P. } \\& \left(\frac{2 b}{3 c}\right)^2=\frac{a}{2 b} \times \frac{3 c}{a} \\& \frac{b}{c}=\frac{3}{2}\end{aligned}amp;loge(2ba),loge(3c2b),loge(a3c) are in A.P. amp;(3c2b)2=2ba×a3camp;cb=23 Putting in eq. (i) b2=a×2b3b^2=a \times \frac{2 b}{3}b2=a×32b amp;ab=32amp;a:b:c=9:6:4\begin{aligned}& \frac{\mathrm{a}}{\mathrm{b}}=\frac{3}{2} \\& \mathrm{a}: \mathrm{b}: \mathrm{c}=9: 6: 4\end{aligned}amp;ba=23amp;a:b:c=9:6:4 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring