Verified Solution • 2025–26 Session moderate

QJEEM24Ma9731: JEE Main 2024 Mathematics - Class 11 JEEM24Ma9731 Solution: If are in an A.P. and a are also in an A.P, then is equal to

If log⁡ea,log⁡e b,log⁡ec\log _e \mathrm{a}, \log _e \mathrm{~b}, \log _e \mathrm{c} are in an A.P. and log⁡ea−log⁡e2 b,log⁡e2 b−log⁡e3c,log⁡e3c−log⁡e\log _e \mathrm{a}-\log _e 2 \mathrm{~b}, \log _e 2 \mathrm{~b}-\log _e 3 \mathrm{c}, \log _e 3 \mathrm{c} -\log _e a are also in an A.P, then a:b:ca: b: c is equal to

Multiple Choice Options

  • A 6:3:26: 3: 2
  • B 9:6:49: 6: 4
  • C 25:10:425: 10: 4
  • D 16:4:116: 4: 1

Step-by-Step Verified Solution

log⁡ea,log⁡eb,log⁡ec\log _{\mathrm{e}} \mathrm{a}, \log _{\mathrm{e}} \mathrm{b}, \log _{\mathrm{e}} \mathrm{c} are in A.P.

∴b2=ac\therefore \mathrm{b}^2=\mathrm{ac} ..... (i)

Also

amp;log⁡e(a2b),log⁡e(2b3c),log⁡e(3ca) are in A.P. amp;(2b3c)2=a2b×3caamp;bc=32\begin{aligned}& \log _e\left(\frac{a}{2 b}\right), \log _e\left(\frac{2 b}{3 c}\right), \log _e\left(\frac{3 c}{a}\right) \text { are in A.P. } \\& \left(\frac{2 b}{3 c}\right)^2=\frac{a}{2 b} \times \frac{3 c}{a} \\& \frac{b}{c}=\frac{3}{2}\end{aligned}

Putting in eq. (i) b2=a×2b3b^2=a \times \frac{2 b}{3}

amp;ab=32amp;a:b:c=9:6:4\begin{aligned}& \frac{\mathrm{a}}{\mathrm{b}}=\frac{3}{2} \\& \mathrm{a}: \mathrm{b}: \mathrm{c}=9: 6: 4\end{aligned}

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