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QJEEM24Ma8eaa: JEE Main 2024 Mathematics - Class 12 JEEM24Ma8eaa Solution: Let . If for some , then , where denotes the greatest integer…

Let f(x)={x−1,x is even, 2x,x is odd, x∈Nf(x)=\left\{\begin{array}{l}x-1, x \text { is even, } \\ 2 x, \quad x \text { is odd, }\end{array} x \in \mathbf{N}\right. .

If for some a∈N,f(f(f(a)))=21\mathrm{a} \in \mathbf{N}, f(f(f(\mathrm{a})))=21 , then lim⁡x→a−{∣x∣3a−[xa]}\lim\limits_{x \rightarrow \mathrm{a}^{-}}\left\{\frac{|x|^3}{\mathrm{a}}-\left[\frac{x}{\mathrm{a}}\right]\right\} , where [t][t] denotes the greatest integer less than or equal to tt , is equal to :

Multiple Choice Options

  • A 169
  • B 121
  • C 225
  • D 144

Step-by-Step Verified Solution

f(x)={x−1,x is even, 2x,x is odd, x∈Nf(x)=\left\{\begin{array}{l}x-1, x \text { is even, } \\ 2 x, \quad x \text { is odd, }\end{array} x \in \mathbf{N}\right.

Let aa is odd

amp;⇒f(a)=2aamp;⇒f(f(a))=2a−1amp;⇒f(f(f(a)))=2(2a−1)\begin{aligned}& \Rightarrow f(a)=2 a \\\\& \Rightarrow f(f(a))=2 a-1 \\\\& \Rightarrow f(f(f(a)))=2(2 a-1)\end{aligned}

2(2a−1)=212(2 a-1)=21 Not possible for any a∈Na \in N

Let aa is even

amp;⇒f(a)=a−1amp;⇒f(f(a))=2(a−1)amp;⇒f(f(f(a)))=2(a−1)−1=2a−3amp;2a−3=21⇒a=12\begin{aligned}& \Rightarrow f(a)=a-1 \\\\& \Rightarrow f(f(a))=2(a-1) \\\\& \Rightarrow f(f(f(a)))=2(a-1)-1=2 a-3 \\\\& 2 a-3=21 \quad \Rightarrow a=12\end{aligned}

Now

amp;lim⁡x→12−(∣x∣32−[x12])amp;=lim⁡x→12−∣x∣312−lim⁡x→12−[x12]amp;=144−0=144.\begin{aligned}& \lim _{x \rightarrow 12^{-}}\left(\frac{|x|^3}{2}-\left[\frac{x}{12}\right]\right) \\\\& =\lim _{x \rightarrow 12^{-}} \frac{|x|^3}{12}-\lim _{x \rightarrow 12^{-}}\left[\frac{x}{12}\right] \\\\& =144-0=144 .\end{aligned}

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