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QJEEM24Ma8d63: JEE Main 2024 Mathematics - Class 12 JEEM24Ma8d63 Solution: The value of lim x → 0 2 ( 1 − cos ⁡ x cos ⁡ 2 x cos ⁡ 3 x 3 ……

The value of limx→02(1−cos⁡xcos⁡2xcos⁡3x3…….cos⁡10x10x2) is __________.

Step-by-Step Verified Solution

lim⁡x→02(1−cos⁡x(cos⁡2x)12(cos⁡3x)13 ... (cos⁡10x)110x2)\mathop {\lim }\limits_{x \to 0} 2\left( {{{1 - \cos x{{(\cos 2x)}^{{1 \over 2}}}{{(\cos 3x)}^{{1 \over 3}}}\,...\,{{(\cos 10x)}^{{1 \over {10}}}}} \over {{x^2}}}} \right) (00 form )\left(\frac{0}{0} \text { form }\right)

Using L' hospital

2limx→0sin⁡x(cos⁡2x)12…(cos⁡10x)110…(sin⁡2x)(cos⁡x)(cos⁡3x)13+…2x

⇒amp;lim⁡x→0(sin⁡xx+sin⁡2xx+…+sin⁡10xx)amp;=1+2+…+10=55\begin{aligned}\Rightarrow & \lim _{x \rightarrow 0}\left(\frac{\sin x}{x}+\frac{\sin 2 x}{x}+\ldots+\frac{\sin 10 x}{x}\right) \\\quad & =1+2+\ldots+10=55\end{aligned}

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