Verified Solution • 2025–26 Session moderate QJEEM24Ma8d63: JEE Main 2024 Mathematics - Class 12 JEEM24Ma8d63 Solution: The value of lim x → 0 2 ( 1 − cos x cos 2 x cos 3 x 3 …… The value of limx→02(1−cosxcos2xcos3x3…….cos10x10x2) is __________. Step-by-Step Verified Solution limx→02(1−cosx(cos2x)12(cos3x)13 ... (cos10x)110x2)\mathop {\lim }\limits_{x \to 0} 2\left( {{{1 - \cos x{{(\cos 2x)}^{{1 \over 2}}}{{(\cos 3x)}^{{1 \over 3}}}\,...\,{{(\cos 10x)}^{{1 \over {10}}}}} \over {{x^2}}}} \right)x→0lim2(x21−cosx(cos2x)21(cos3x)31...(cos10x)101) (00 form )\left(\frac{0}{0} \text { form }\right)(00 form ) Using L' hospital 2limx→0sinx(cos2x)12…(cos10x)110…(sin2x)(cosx)(cos3x)13+…2x ⇒amp;limx→0(sinxx+sin2xx+…+sin10xx)amp;=1+2+…+10=55\begin{aligned}\Rightarrow & \lim _{x \rightarrow 0}\left(\frac{\sin x}{x}+\frac{\sin 2 x}{x}+\ldots+\frac{\sin 10 x}{x}\right) \\\quad & =1+2+\ldots+10=55\end{aligned}⇒amp;x→0lim(xsinx+xsin2x+…+xsin10x)amp;=1+2+…+10=55 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring