QJEEM24Ma76c3: JEE Main 2024 Mathematics - Class 12 JEEM24Ma76c3 Solution: The area of the region enclosed by the parabolas and is ________.

$\begin{aligned}y=x^2-5 x, y=7 x-x^2 & \Rightarrow \quad x^2-5 x=7 x-x^2 \\& \Rightarrow \quad x=0, x=6\end{aligned}$

$$\text{ Area }=\underset{0}{\overset{6}{\int }}[(7x-x^2)-(x-5x)]dx$$

$$=\underset{0}{\overset{6}{\int }}(12x-2x^2)dx=6x-{\frac{2x^3}{3}|}_0^6$$

$=216-144=72 \text { sq. unit }$

But answer is 198 as per NTA.