amp; Let p=2r,q=2r2amp;T7=2,T8=2r,T13=2r2amp;d=2r−2=2(r−1)amp;2r2=T7+6d=2+6(2)(r−1)=12r−10amp;⇒r2−6r+5=0amp;⇒(r−1)(r−5)=0amp;∴r=1,5amp;r=1 (rejected) as q=2amp;∴r=5
5th term of G.P =2.r4=2.54
Let 1st term of A.P ba=a,d=8
2=a+(6)(8)⇒a=−46
nth term of A.P =−46+(n−1)8=8n−54
amp;2.54=8n−54amp;⇒1250+54=8namp;⇒n=81304=163