∣x∣∣x+2∣−5∣x+1∣−1=0

amp; (I) if xamp;x2+2x+5x+5−1=0amp;x2+7x+4=0⇒ one root satisfying xlt;−2lt;−2
amp; (II) if −2≤xamp;−x2−2x+5x+5−1=0amp;x2−3x−4=0⇒ not root satisfying −2≤xlt;−1lt;−1
amp; (III) if −1≤xamp;−x2−2x−5x−5−1=0amp;x2+7x+6=0amp;x=−1 is only root satisfying −1≤xlt;0lt;0
(IV) if x≥0
amp;x2+2x−5x−5−1=0amp;x2−3x−6=0
one root satisfying x≥0
⇒ The number of distinct real roots are three.