Verified Solution • 2025–26 Session moderate

QJEEM24Ma4800: JEE Main 2024 Mathematics - Class 11 JEEM24Ma4800 Solution: The number of distinct real roots of the equation is __________.

The number of distinct real roots of the equation ∣x∣∣x+2∣−5∣x+1∣−1=0|x||x+2|-5|x+1|-1=0 is __________.

Step-by-Step Verified Solution

∣x∣∣x+2∣−5∣x+1∣−1=0|x| \quad|x+2|-5|x+1|-1=0

JEE Main 2024 (Online) 5th April Morning Shift Mathematics - Quadratic Equation and Inequalities Question 13 English Explanation

amp; (I) if xlt;−2amp;x2+2x+5x+5−1=0amp;x2+7x+4=0⇒ one root satisfying xlt;−2\begin{aligned}& \text { (I) if } x<-2 \\& x^2+2 x+5 x+5-1=0 \\& x^2+7 x+4=0 \Rightarrow \text { one root satisfying } x<-2\end{aligned}

amp; (II) if −2≤xlt;−1amp;−x2−2x+5x+5−1=0amp;x2−3x−4=0⇒ not root satisfying −2≤xlt;−1\begin{aligned}& \text { (II) if }-2 \leq x<-1 \\& -x^2-2 x+5 x+5-1=0 \\& x^2-3 x-4=0 \Rightarrow \text { not root satisfying }-2 \leq x<-1\end{aligned}

amp; (III) if −1≤xlt;0amp;−x2−2x−5x−5−1=0amp;x2+7x+6=0amp;x=−1 is only root satisfying −1≤xlt;0\begin{aligned}& \text { (III) if }-1 \leq x<0 \\& -x^2-2 x-5 x-5-1=0 \\& x^2+7 x+6=0 \\& x=-1 \text { is only root satisfying }-1 \leq x<0\end{aligned}

(IV) if x≥0x \geq 0

amp;x2+2x−5x−5−1=0amp;x2−3x−6=0\begin{aligned}& x^2+2 x-5 x-5-1=0 \\& x^2-3 x-6=0\end{aligned}

one root satisfying x≥0x \geq 0

⇒\Rightarrow The number of distinct real roots are three.

Related Learning Resources & Exam Preparation