Verified Solution • 2025–26 Session moderate QJEEM24Ma2634: JEE Main 2024 Mathematics - Class 11 JEEM24Ma2634 Solution: If , then range of is If f(x)={2+2x,amp;−1≤xlt;01−x3,amp;0≤x≤3;g(x)={−x,amp;−3≤x≤0x,amp;0lt;x≤1f(x)=\left\{\begin{array}{cc}2+2 x, & -1 \leq x < 0 \\ 1-\frac{x}{3}, & 0 \leq x \leq 3\end{array} ; g(x)=\left\{\begin{array}{cc}-x, & -3 \leq x \leq 0 \\ x, & 0 < x \leq 1\end{array}\right.\right.f(x)={2+2x,1−3x,amp;−1≤xamp;0≤x≤3lt;0;g(x)={−x,x,amp;−3≤x≤0amp;0lt;x≤1 , then range of (fog)(x)(f o g)(x)(fog)(x) is Multiple Choice Options A [0,1)[0,1)[0,1) B [0,3)[0,3)[0,3) C (0,1](0,1](0,1] D [0,1][0,1][0,1] Step-by-Step Verified Solution f(g(x))={2+2g(x),−1≤g(x)<0.....(1)1−g(x)3,0≤g(x)≤3.....(2) By (1) x∈ϕ\text { By (1) } x \in \phi By (1) x∈ϕ And by (2) x∈[−3,0]x \in[-3,0]x∈[−3,0] and x∈[0,1]x \in[0,1]x∈[0,1] Range of f(g(x))\mathrm{f(g(x))}f(g(x)) is [0,1][0,1][0,1] Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring
