Verified Solution • 2025–26 Session moderate

QJEEM24Ma203a: JEE Main 2024 Mathematics - Class 11 JEEM24Ma203a Solution: The sum of all rational terms in the expansion of is equal to :

The sum of all rational terms in the expansion of (215+513)15\left(2^{\frac{1}{5}}+5^{\frac{1}{3}}\right)^{15} is equal to :

Multiple Choice Options

  • A 633
  • B 6131
  • C 3133
  • D 931

Step-by-Step Verified Solution

amp;Tr+1=15Cr(21/5)15−r(51/3)ramp;=15Cr5r/32(3−r5)\begin{aligned}& T_{r+1}={ }^{15} \mathrm{C}_r\left(2^{1 / 5}\right)^{15-r}\left(5^{1 / 3}\right)^r \\& ={ }^{15} C_r 5^{r / 3} 2^{\left(3-\frac{r}{5}\right)}\end{aligned}

For rational terms,

r3\frac{r}{3} and r5\frac{r}{5} must be integer

3 and 5 divide r⇒15r \Rightarrow 15 divides r⇒r=0r \Rightarrow r=0 and r=15r=15

15C05023+15C15552(0){ }^{15} C_0 5^0 2^3+{ }^{15} C_{15} 5^5 2^{(0)}

amp;=8+3125amp;=3133\begin{aligned}& =8+3125 \\& =3133\end{aligned}

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