Verified Solution • 2025–26 Session moderate

QJEEM24Ma050a: JEE Main 2024 Mathematics - Class 11 JEEM24Ma050a Solution: Let M denote the median of the following frequency distribution …

Let M denote the median of the following frequency distribution

Class 0 - 4 4 - 8 8 - 12 12 - 16 16 - 20
Frequency 3 9 10 8 6

Then 20M is equal to :

Multiple Choice Options

  • A 104
  • B 52
  • C 208
  • D 416

Step-by-Step Verified Solution

Class Frequency Cumulative
frequency
0-4 3 3
4-8 9 12
8-12 10 22
12-16 8 30
16-20 6 36

amp;M=1+(N2−Cf)hamp;M=8+18−1210×4amp;M=10.4amp;20M=208\begin{aligned}& \mathrm{M}=1+\left(\frac{\frac{\mathrm{N}}{2}-\mathrm{C}}{\mathrm{f}}\right) \mathrm{h} \\& \mathrm{M}=8+\frac{18-12}{10} \times 4 \\& \mathrm{M}=10.4 \\& 20 \mathrm{M}=208\end{aligned}

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