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QJEEM24Chffcc: JEE Main 2024 Chemistry - Class 11 JEEM24Chffcc Solution: A hypothetical electromagnetic wave is show below. The…

A hypothetical electromagnetic wave is show below.

JEE Main 2024 (Online) 8th April Morning Shift Chemistry - Structure of Atom Question 17 English

The frequency of the wave is x×1019 Hz\mathrm{x} \times 10^{19} \mathrm{~Hz} .

x=\mathrm{x}= _________ (nearest integer)

Step-by-Step Verified Solution

λamp;=1.5×4=6 pmνamp;=Cλνamp;=3×1086×10−12amp;=0.5×1020νamp;=5×1019xamp;=5\begin{aligned}\lambda & =1.5 \times 4=6 \mathrm{~pm} \\\nu & =\frac{C}{\lambda} \\\nu & =\frac{3 \times 10^8}{6 \times 10^{-12}} \\& =0.5 \times 10^{20} \\\nu & =5 \times 10^{19} \\x & =5\end{aligned}

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