QJEEM24Chf269: JEE Main 2024 Chemistry - Class 11 JEEM24Chf269 Solution: The Molarity (M) of an aqueous solution containing 5.85 g of…
The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is : (Given : Molar Mass Na:23 and Cl:35.5 gmol−1)
Multiple Choice Options
- A 20
- B 4
- C 2
- D 0.2
Step-by-Step Verified Solution
To find the molarity of the aqueous solution, we need to calculate the number of moles of NaCl and then divide it by the volume of the solution in liters.
First, determine the molar mass of NaCl:
Molar mass of NaCl=Molar mass of Na+Molar mass of Cl=23+35.5=58.5g/mol
Next, calculate the moles of NaCl:
Moles of NaCl=5.85g58.5g/mol=0.1mol
Now, convert the volume of the solution from milliliters to liters:
500mL=0.500L
Finally, calculate the molarity (M), which is the number of moles of solute per liter of solution:
M=Moles of NaClVolume of solution in liters=0.1mol0.500L=0.2M
Therefore, the molarity of the solution is 0.2 M. The correct option is D.