QJEEM24Chdad5: JEE Main 2024 Chemistry - Class 12 JEEM24Chdad5 Solution: The osmotic pressure of a dilute solution is 7 × 10 5   Pa …

To calculate the osmotic pressure of the solution at the new temperature, we can use the formula:

$\pi = \text{CRT}$

Since the concentration $C$ and the gas constant $R$ remain constant, the ratio of the osmotic pressures at two different temperatures is given by:

$\frac{\pi_1}{\pi_2} = \frac{T_1}{T_2}$

Thus, we can express the osmotic pressure at the second temperature as:

$\pi_2 = \frac{\pi_1 \cdot T_2}{T_1}$

Substituting the given values:

$\pi_2 = \frac{7 \times 10^5 \times 283}{273}$

After calculation, this simplifies to:

$\pi_2 = 72.56 \times 10^4 \, \text{Nm}^{-2}$