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QJEEM24Chdab3: JEE Main 2024 Chemistry - Class 11 JEEM24Chdab3 Solution: Choose the correct option for free expansion of an ideal gas…

Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following :

Multiple Choice Options

  • A q=0,ΔT=0,w=0\mathrm{q}=0, \Delta \mathrm{T}=0, \mathrm{w}=0
  • B q=0,ΔT≠0,w=0\mathrm{q}=0, \Delta \mathrm{T} \neq 0, \mathrm{w}=0
  • C q≠0,ΔT=0,w=0\mathrm{q} \neq 0, \Delta \mathrm{T}=0, \mathrm{w}=0
  • D q=0,ΔT<0,w≠0\mathrm{q}=0, \Delta \mathrm{T}<0, \mathrm{w} \neq 0

Step-by-Step Verified Solution

Let's analyze what happens during a free (or unrestrained) expansion of an ideal gas under adiabatic conditions:

  • Adiabatic process : By definition, in an adiabatic process, no heat is transferred between the system and its surroundings. Thus, q=0q = 0 .

  • Free expansion : In a free expansion, the gas expands into a vacuum or against zero external pressure. Since work ( ww ) is defined as the product of pressure ( PP ) and volume change ( ΔV\Delta V ), and since the external pressure is zero, we conclude that w=0w = 0 .

  • Temperature change ( ΔT\Delta T ) : Since work is zero and no heat is transferred, the first law of thermodynamics tells us that the change in internal energy ( ΔU\Delta U ) is zero as well. For an ideal gas, internal energy is a function of temperature only; thus, if the internal energy does not change, the temperature does not change. Therefore, ΔT=0\Delta T = 0 .

Based on the above points, the free expansion of an ideal gas under adiabatic conditions is characterized by no heat transfer ( q=0q = 0 ), no work done ( w=0w = 0 ), and no change in temperature ( ΔT=0\Delta T = 0 ). Therefore, the correct option is:

Option A : q=0,ΔT=0,w=0q = 0, \Delta T = 0, w = 0

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