Verified Solution • 2025–26 Session moderate

QJEEM24Chd98b: JEE Main 2024 Chemistry - Class 12 JEEM24Chd98b Solution: The orange colour of and purple colour of is due to

The orange colour of K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 and purple colour of KMnO4\mathrm{KMnO}_4 is due to

Multiple Choice Options

  • A Charge transfer transition in both.
  • B d→d\mathrm{d} \rightarrow \mathrm{d} transitions in KMnO4\mathrm{KMnO}_4 and charge transfer transitions in K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 .
  • C d→d\mathrm{d} \rightarrow \mathrm{d} transitions in both
  • D d→d\mathrm{d} \rightarrow \mathrm{d} transitions in K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 and charge transfer transitions in KMnO4\mathrm{KMnO}_4 .

Step-by-Step Verified Solution

K2Cr2O7→Cr+6→ No d - d transition KMnO4→Mn7+→ No d - d transition } Charge transfer \left.\begin{array}{l}\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \rightarrow \mathrm{Cr}^{+6} \rightarrow \text { No d - d transition } \\\mathrm{KMnO}_4 \rightarrow \mathrm{Mn}^{7+} \rightarrow \text { No d - d transition }\end{array}\right\} \text { Charge transfer }

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