Verified Solution • 2025–26 Session moderate

QJEEM24Chd665: JEE Main 2024 Chemistry - Class 12 JEEM24Chd665 Solution: Consider the following reaction Product ' ' in neutral or…

Consider the following reaction

MnO2+KOH+O2→A+H2O. \mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{A}+\mathrm{H}_2 \mathrm{O} \text {. }

Product ' A\mathrm{A} ' in neutral or acidic medium disproportionate to give products ' B\mathrm{B} ' and ' C\mathrm{C} ' along with water. The sum of spin-only magnetic moment values of B\mathrm{B} and C\mathrm{C} is ________ BM. (nearest integer) (Given atomic number of Mn\mathrm{Mn} is 25)

Step-by-Step Verified Solution

A\mathrm{A} is K2MnO4\mathrm{K}_2 \mathrm{MnO}_4

B\mathrm{B} and C\mathrm{C} are KMnO4\mathrm{KMnO}_4 and MnO2\mathrm{MnO}_2

KMnO4(μ=0)\mathrm{KMnO}_4(\mu=0)

MnO2(Mn4+)(μ=3.87)\mathrm{MnO}_2(\mathrm{Mn}^{4+})(\mu=3.87)

Sum =3.87=4=3.87=4 (Nearest integer)

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