Verified Solution • 2025–26 Session moderate

QJEEM24Chd46e: JEE Main 2024 Chemistry - Class 11 JEEM24Chd46e Solution: A solution of is by mass and has a density of . The molarity of …

A solution of H2SO4\mathrm{H}_2 \mathrm{SO}_4 is 31.4%H2SO431.4 \% \mathrm{H}_2 \mathrm{SO}_4 by mass and has a density of 1.25 g/mL1.25 \mathrm{~g} / \mathrm{mL} . The molarity of the H2SO4\mathrm{H}_2 \mathrm{SO}_4 solution is _________ M\mathrm{M} (nearest integer)

[Given molar mass of H2SO4=98 g mol−1\mathrm{H}_2 \mathrm{SO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1} ]

Step-by-Step Verified Solution

amp;M=nsolute V×1000amp;=(31.498)(1001.25)×1000amp;=4.005≈4\begin{aligned}& M=\frac{n_{\text {solute }}}{V} \times 1000 \\& =\frac{\left(\frac{31.4}{98}\right)}{\left(\frac{100}{1.25}\right)} \times 1000 \\& =4.005 \approx 4\end{aligned}

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