Verified Solution • 2025–26 Session moderate

QJEEM24Chd07d: JEE Main 2024 Chemistry - Class 11 JEEM24Chd07d Solution: If the above equation is balanced with integer coefficients,…

2MnO4−+bI−+cH2O→xI2+yMnO2+zO‾H2 \mathrm{MnO}_4^{-}+\mathrm{bI}^{-}+\mathrm{cH}_2 \mathrm{O} \rightarrow x \mathrm{I}_2+y \mathrm{MnO}_2+z \overline{\mathrm{O}} \mathrm{H}

If the above equation is balanced with integer coefficients, the value of zz is ________.

Step-by-Step Verified Solution

Reduction Half Oxidation Half
2MnO4−→2MnO22 \mathrm{MnO}_4^{-} \rightarrow 2 \mathrm{MnO}_2 2I−→I2+2e−2 \mathrm{I}^{-} \rightarrow \mathrm{I}_2+2 \mathrm{e}^{-}
2MnO4−+4H2O+6e−→2MnO2+8OH−2 \mathrm{MnO}_4^{-}+4 \mathrm{H}_2 \mathrm{O}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{MnO}_2+8 \mathrm{OH}^{-} 6I−→3I2+6e−6 \mathrm{I}^{-} \rightarrow 3 \mathrm{I}_2+6 \mathrm{e}^{-}

Adding oxidation half and reduction half, net reaction is

amp;2MnO4−+6I−+4H2O→3I2+2MnO2+8OH−⇒amp;z=8⇒amp; Ans 8\begin{aligned}& 2 \mathrm{MnO}_4^{-}+6 \mathrm{I}^{-}+4 \mathrm{H}_2 \mathrm{O} \rightarrow 3 \mathrm{I}_2+2 \mathrm{MnO}_2+8 \mathrm{OH}^{-} \\\Rightarrow \quad & \mathrm{z}=8 \\\Rightarrow \quad & \text { Ans } 8\end{aligned}

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