QJEEM24Chd039: JEE Main 2024 Chemistry - Class 12 JEEM24Chd039 Solution: A conductivity cell with two electrodes (dark side) are half…

The molar conductivity, denoted as $${\wedge }_m$$, is calculated using the formula:

$${\wedge }_m=\frac{\mathrm{K}\times 1000}{\mathrm{M}}$$

When the volume of the solution is doubled by adding more water at a constant temperature, the conductivity, $$\mathrm{K}$$, will be reduced to half, while the molarity, $$\mathrm{M}$$, will also be halved.

Therefore, the molar conductivity $${\lambda }_{\mathrm{m}}$$ will either remain the same or cannot be measured with sharp accuracy.

For an infinitely dilute solution, the molar conductivity $${\wedge }_{\mathrm{m}}$$ is approximately equal to the molar conductivity at infinite dilution $${\wedge }_{\mathrm{m}}^0$$, which is a constant.