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QJEEM24Chcbb1: JEE Main 2024 Chemistry - Class 11 JEEM24Chcbb1 Solution: Number of moles of methane required to produce 22   g…

Number of moles of methane required to produce 22 g CO2( g) after combustion is x×10−2 moles. The value of x is _________.

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CH4( g)+2O2( g)→CO2( g)+2H2O(ℓ)

nCO2=2244=0.5 moles 

So moles of CH4 required =0.5 moles i.e. 50×10−2 mole

x=50

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