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QJEEM24Chcb49: JEE Main 2024 Chemistry - Class 12 JEEM24Chcb49 Solution: Match List - I with List - II . table { border-collapse:…

Match List - I with List - II.

List I (Reactions) List II (Reagents)
(A) JEE Main 2024 (Online) 1st February Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 43 English 1 (I) CH3MgBr, H2O
(B) C6H5COC6H5 ⟶ C6H5CH=C6H5 (II) Zn(Hg) and conc. HCl
(C) C6H5CHO ⟶ C6H5CH(OH)CH3 (III) NaBH4, H+
(D) JEE Main 2024 (Online) 1st February Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 43 English 2 (IV) DIBAL-H, H2O


Choose the correct answer from the options given below :

Multiple Choice Options

  • A (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  • B (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  • C (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  • D (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-Step Verified Solution

JEE Main 2024 (Online) 1st February Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 43 English Explanation

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