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QJEEM24Chbe2d: JEE Main 2024 Chemistry - Class 12 JEEM24Chbe2d Solution: The quantity of silver deposited when one coulomb charge is…

The quantity of silver deposited when one coulomb charge is passed through AgNO3\mathrm{AgNO}_3 solution :

Multiple Choice Options

  • A 0.1 g0.1 \mathrm{~g} atom of silver
  • B 1 chemical equivalent of silver
  • C 1 g1 \mathrm{~g} of silver
  • D 1 electrochemical equivalent of silver

Step-by-Step Verified Solution

To determine the quantity of silver deposited when one coulomb of charge is passed through AgNO3\mathrm{AgNO}_3 solution, we need to refer to Faraday's laws of electrolysis, especially to the concept of the electrochemical equivalent. The electrochemical equivalent (ECE) of a substance is the amount of the substance that is deposited or dissolved at an electrode during electrolysis by one coulomb of charge.

The electrochemical equivalent of a substance can be calculated using the formula:

E=MnFE = \frac{M}{nF}

where:

  • EE is the electrochemical equivalent of the substance in grams per coulomb ( g/C\mathrm{g/C} ).
  • MM is the molar mass of the substance in grams per mole ( g/mol\mathrm{g/mol} ).
  • nn is the number of electrons involved in the oxidation or reduction reaction (the valency).
  • FF is the Faraday constant, approximately 96485 C/mol96485 \, \mathrm{C/mol} , which is the charge of one mole of electrons.

In the case of silver ( Ag\mathrm{Ag} ) being deposited from AgNO3\mathrm{AgNO}_3 , when silver ion ( Ag+\mathrm{Ag}^+ ) is reduced to metallic silver ( Ag\mathrm{Ag} ), the reaction involves one electron ( n=1n = 1 ). The molar mass of silver (Ag) is approximately 107.868 g/mol107.868 \, \mathrm{g/mol} . Using this information:

E=107.868 g/mol1⋅96485 C/mol≈0.001118 g/CE = \frac{107.868 \, \mathrm{g/mol}}{1 \cdot 96485 \, \mathrm{C/mol}} \approx 0.001118 \, \mathrm{g/C}

This means that for every coulomb of charge passed through the solution, 0.001118 g0.001118 \, \mathrm{g} of silver is deposited.

Given the options:

  • Option A: 0.10.1 g atom of silver - This is incorrect because the calculation shows a much smaller amount is deposited per coulomb.
  • Option B: 1 chemical equivalent of silver - This does not directly relate to the amount deposited per coulomb.
  • Option C: 1 g1 \mathrm{~g} of silver - This is incorrect as it overestimates the amount deposited by a large margin.
  • Option D: 1 electrochemical equivalent of silver - This is correct, as it directly relates to the amount of a substance deposited by one coulomb of charge, based on the formula and calculation shown.

Therefore, the correct answer is Option D: 1 electrochemical equivalent of silver.

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