Verified Solution • 2025–26 Session moderate QJEEM24Chb623: JEE Main 2024 Chemistry - Class 11 JEEM24Chb623 Solution: Total number of electrons present in molecular orbitals of and… Total number of electrons present in (π∗)\left(\pi^*\right)(π∗) molecular orbitals of O2,O2+\mathrm{O}_2, \mathrm{O}_2^{+}O2,O2+ and O2−\mathrm{O}_2^{-}O2− is ________. Step-by-Step Verified Solution amp;O2(16e):(σ1 s)2(σ1 s∗)2(σ2 s)2(σ2 s∗)2amp;(σ2p)2[(π2p)2=(π2p)2],[(π2p∗)1=(π2p∗)1]\begin{aligned}& \mathrm{O}_2(16 \mathrm{e}):\left(\sigma_{1 \mathrm{~s}}\right)^2\left(\sigma_{1 \mathrm{~s}}^*\right)^2\left(\sigma_{2 \mathrm{~s}}\right)^2\left(\sigma_{2 \mathrm{~s}}^*\right)^2 \\& \left(\sigma_{2 \mathrm{p}}\right)^2\left[\left(\pi_{2 \mathrm{p}}\right)^2=\left(\pi_{2 \mathrm{p}}\right)^2\right],\left[\left(\pi_{2 \mathrm{p}}^*\right)^1=\left(\pi_{2 \mathrm{p}}^*\right)^1\right]\end{aligned}amp;O2(16e):(σ1 s)2(σ1 s∗)2(σ2 s)2(σ2 s∗)2amp;(σ2p)2[(π2p)2=(π2p)2],[(π2p∗)1=(π2p∗)1] Number of e−\mathrm{e}^{-}e− present in (π∗)\left(\pi^*\right)(π∗) of O2=2\mathrm{O}_2=2O2=2 Number of e−\mathrm{e}^{-}e− present in (π∗)\left(\pi^*\right)(π∗) of O2+=1\mathrm{O}_2^{+}=1O2+=1 Number of e−\mathrm{e}^{-}e− present in (π∗)\left(\pi^*\right)(π∗) of O2−=3\mathrm{O}_2^{-}=3O2−=3 So total e−\mathrm{e}^{-}e− in (π∗)=2+1+3=6\left(\pi^*\right)=2+1+3=6(π∗)=2+1+3=6 Related Learning Resources & Exam Preparation JEE Main PYQ Question Bank Browse year-wise authentic previous years' questions with solutions Authentic CBT Mock Tests Simulate official exam environment with live timer and percentile scoring