QJEEM24Chb2f0: JEE Main 2024 Chemistry - Class 11 JEEM24Chb2f0 Solution: Number of and bonds present in ethylene molecule is…

Let's analyze the bond structure in an ethylene molecule (C₂H₄) to determine the count of $\sigma$ and $\pi$ bonds.

Ethylene consists of two carbon atoms double-bonded to each other, with each carbon atom also bonded to two hydrogen atoms. Each single bond is a $\sigma$ bond. The double bond between the carbon atoms is made up of one $\sigma$ bond and one $\pi$ bond. Here's how the bonds break down:

1. Each carbon-hydrogen bond is a $\sigma$ bond. Since there are four C-H bonds, we have 4 $\sigma$ bonds from C-H bonding.
2. The carbon-carbon double bond consists of one $\sigma$ bond and one $\pi$ bond. Thus, we have 1 additional $\sigma$ bond from the C=C double bond.
3. Total $\sigma$ bonds = 4 (from C-H) + 1 (from C=C) = 5.
4. There is 1 $\pi$ bond present in the carbon-carbon double bond.

Therefore, the correct option is:

Option B: 5 and 1