QJEEM24Chb1c0: JEE Main 2024 Chemistry - Class 12 JEEM24Chb1c0 Solution: Identify B formed in the reaction. Cl − ( CH 2 ) 4 − Cl →…

Multiple Choice Options

• A Cl−N+H3−(CH2)4−N+H3Cl−
• B H2N−(CH2)4−NH2
• C $\stackrel{-}{\mathrm{Cl}}\stackrel{+}{\mathrm{N}} \mathrm{H}_3-\left(\mathrm{CH}_2\right)_4-\stackrel{+}{\mathrm{N}} \mathrm{H}_3 \mathrm{Cl}^{-}$ Cl _ N + _ H 3 _ _ ( CH 2 _ ) 4 _ _ N + _ H 3 _ Cl _
• D $\mathrm{H}_2 \mathrm{N}-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2$ H 2 _ N _ ( CH 2 _ ) 4 _ _ NH 2 _