Verified Solution • 2025–26 Session moderate

QJEEM24Chaf7b: JEE Main 2024 Chemistry - Class 12 JEEM24Chaf7b Solution: Identify the incorrect statements about group 15 elements : (A) …

Identify the incorrect statements about group 15 elements :

(A) Dinitrogen is a diatomic gas which acts like an inert gas at room temperature.

(B) The common oxidation states of these elements are −3,+3-3,+3 and +5.

(C) Nitrogen has unique ability to form pπ−pπ\mathrm{p} \pi-\mathrm{p} \pi multiple bonds.

(D) The stability of +5 oxidation states increases down the group.

(E) Nitrogen shows a maximum covalency of 6.

Choose the correct answer from the options given below :

Multiple Choice Options

  • A (A), (C), (E) only
  • B (D) and (E) only
  • C (A), (B), (D) only
  • D (B), (D), (E) only

Step-by-Step Verified Solution

Let's analyze each statement step by step to identify the incorrect ones:

(A) Dinitrogen is a diatomic gas which acts like an inert gas at room temperature.

This statement is generally correct. Dinitrogen ( N2N_2 ) is indeed a diatomic gas and is very inert at room temperature due to the strong triple bond between the nitrogen atoms.

(B) The common oxidation states of these elements are −3,+3-3,+3 and +5.

This statement is also correct. The group 15 elements commonly exhibit oxidation states of −3-3 (in nitrides), +3+3 (as in NH3\mathrm{NH}_3 ), and +5 (as in HNO3\mathrm{HNO_3} ).

(C) Nitrogen has unique ability to form pπ−pπ\mathrm{p}\pi-\mathrm{p}\pi multiple bonds.

This statement is correct. Nitrogen has a unique ability to form pπ−pπp\pi-p\pi multiple bonds, which is why it can form a triple bond ( N2N_2 ).

(D) The stability of +5 oxidation states increases down the group.

This statement is incorrect. The stability of +5 oxidation states actually decreases down the group due to the effect of inert pair effect. For example, bismuth in +5 state is less stable than nitrogen in +5 state.

(E) Nitrogen shows a maximum covalency of 6.

This statement is incorrect. Nitrogen can exhibit a maximum covalency of 4 (as in NH4+\mathrm{NH_4^+} ). It cannot expand its octet to show a covalency of 6.

Based on the above analysis, the incorrect statements are (D) and (E). Therefore, the correct answer is:

Option B: (D) and (E) only

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