Verified Solution • 2025–26 Session moderate

QJEEM24Chaf21: JEE Main 2024 Chemistry - Class 12 JEEM24Chaf21 Solution: The number of neutrons present in the more abundant isotope of…

The number of neutrons present in the more abundant isotope of boron is ' xx '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' yy '. The value of x+yx+y is _________ .

Multiple Choice Options

  • A 9
  • B 6
  • C 4
  • D 3

Step-by-Step Verified Solution

The most abundant isotope of Boron is 5 B11{ }_5 \mathrm{~B}^{11} .

No. of neutrons in it =x=6=x=6

2B(s)+N2(g)→Δ2BN(s)2 \mathrm{B}(\mathrm{s})+\mathrm{N}_2(\mathrm{g}) \xrightarrow{\Delta} 2 \mathrm{BN}(\mathrm{s})

Oxidation state of boron in BN=y=+3\mathrm{B N=y=+3}

So, x+y=6+3x+y=6+3

=9=9

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