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QJEEM24Cha7e4: JEE Main 2024 Chemistry - Class 12 JEEM24Cha7e4 Solution: Consider the following reaction The time taken for A to become…

Consider the following reaction

A+B→C\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}

The time taken for A to become 1/4th 1 / 4^{\text {th }} of its initial concentration is twice the time taken to become 1/21 / 2 of the same. Also, when the change of concentration of B is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis.

The overall order of the reaction is ________.

Step-by-Step Verified Solution

To determine the overall order of the reaction given by A+B→C\mathrm{A} + \mathrm{B} \rightarrow \mathrm{C} , we can derive the information based on the given details about the kinetics of reactant A and the graphical behavior of reactant B.

The first piece of information tells us that the time for the concentration of A to reduce to 1/41/4 of its initial concentration ( [A]0/4[A]_0/4 ) is twice the time it takes to reduce to half of its initial concentration ( [A]0/2[A]_0/2 ). This characteristic is a hallmark of first-order reactions. In first-order reactions, the time it takes for the concentration of the reactant to reduce to half of its initial value (known as the half-life, t1/2t_{1/2} ) is constant and does not depend on the initial concentration. Specifically, the fact that the concentration decreases by a factor of 4 (to 1/41/4 its initial value) in twice the time it takes to decrease by a factor of 2 (to 1/21/2 its initial value) indicates a constant half-life, consistent with first-order kinetics for reactant A.

As for reactant B, the information provided is that a plot of its concentration change over time is a straight line with a negative slope and a positive intercept on the concentration axis. This description matches the behavior of a reactant in a reaction of zero-order kinetics with respect to B, where the rate of reaction is constant and independent of the concentration of B. In zero-order reactions, the concentration of the reactant decreases linearly over time, since the rate of decrease is constant.

Therefore, considering the kinetics of both A and B:

  • Reactant A shows first-order kinetics.
  • Reactant B shows zero-order kinetics.

The overall order of the reaction is the sum of the individual orders with respect to each reactant, which gives us:

Overall order=Order with respect to A+Order with respect to B=1(A)+0(B)=1.\text{Overall order} = \text{Order with respect to A} + \text{Order with respect to B} = 1 (A) + 0 (B) = 1.

Hence, the overall order of the reaction is 1.

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