QJEEM24Cha798: JEE Main 2024 Chemistry - Class 11 JEEM24Cha798 Solution: Given below are two statements : Statement I : On passing HCl ( …
Given below are two statements :
Statement I : On passing
Statement II : When
In the light of the above statements, choose the most appropriate answer from the options given below :
Multiple Choice Options
- A Both Statement I and Statement II are correct
- B Statement I is incorrect but Statement II is correct
- C Both Statement I and Statement II are incorrect
- D Statement I is correct but Statement II is incorrect
Step-by-Step Verified Solution
To determine the correctness of the statements, we'll analyze each one individually by applying principles of solubility, common ion effect, and chemical equilibria.
Statement I:
On passing through a saturated solution of at room temperature, white turbidity appears.
Analysis:
Dissolution of HCl Gas:
When is bubbled through water, it dissolves and dissociates completely:
This increases the concentration of ions in the solution.
Effect on BaCl₂ Solubility:
The solubility equilibrium of in water is:
Adding more shifts the equilibrium to the left (Le Chatelier's Principle), causing to precipitate.
The precipitation of manifests as a white turbidity.
Conclusion:
Statement I is correct.
Statement II:
When gas is passed through a saturated solution of , sodium chloride is precipitated due to common ion effect.
Analysis:
Dissolution of HCl Gas:
Similar to before, increases ion concentration.
Effect on NaCl Solubility:
The solubility equilibrium of is:
However, is highly soluble in water, and its solubility is not significantly affected by the common ion effect from .
The solubility product ( ) of is large, and the addition of ions does not cause to precipitate under normal conditions.
No precipitation occurs; the solution remains clear.
Conclusion:
Statement II is incorrect.
Final Answer:
Statement I is correct but Statement II is incorrect.