Verified Solution • 2025–26 Session moderate

QJEEM24Cha64b: JEE Main 2024 Chemistry - Class 12 JEEM24Cha64b Solution: Match List I with List II .tg…

Match List I with List II

LIST I
(Compound)
LIST II
(Colour]
A. Fe4[Fe(CN)6]3⋅xH2O I. Violet
B. [Fe(CN)5NOS]4− II. Blood Red
C. [Fe(SCN)]2+ III. Prussian Blue
D. (NH4)3PO4⋅12MoO3 IV. Yellow

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A-IV, B-I, C-II, D-III
  • B A-I, B-II, C-III, D-IV
  • C A-II, B-III, C-IV, D-I
  • D A-III, B-I, C-II, D-IV

Step-by-Step Verified Solution

To match List I with List II correctly, we need to identify the colors associated with each compound.

Let's analyze each compound:

1. Fe4[Fe(CN)6]3⋅xH2O - This is known as Prussian Blue.

2. [Fe(CN)5NOS]4− - This complex is known to have a violet color.

3. [Fe(SCN)]2+ - This ion is known for its blood red color.

4. (NH4)3PO4⋅12MoO3 - This is commonly known as Ammonium phosphomolybdate, which is yellow.

Matching each item, we get:

LIST I
(Compound)
LIST II
(Colour)
A. Fe4[Fe(CN)6]3⋅xH2O III. Prussian Blue
B. [Fe(CN)5NOS]4− I. Violet
C. [Fe(SCN)]2+ II. Blood Red
D. (NH4)3PO4⋅12MoO3 IV. Yellow

Based on the analysis, the correct matching is:

Option D: A-III, B-I, C-II, D-IV

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