Verified Solution • 2025–26 Session
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QJEEM24Cha48f: JEE Main 2024 Chemistry - Class 11 JEEM24Cha48f Solution: Match List I with List II. .tg…
Match List I with List II.
| LIST I Alkali Metal | LIST II Emission Wavelength in nm | ||
|---|---|---|---|
| A. | Li | I. | 589.2 |
| B. | Na | II. | 455.5 |
| C. | Rb | III. | 670.8 |
| D. | Cs | IV. | 780.0 |
Choose the correct answer from the options given below :
Multiple Choice Options
- A (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
- B (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- C (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
- D (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
Step-by-Step Verified Solution
To match List I (Alkali Metals) with List II (Emission Wavelength in nm), we need to know the characteristic emission lines of these elements. Here is the information for the typical emission wavelengths:
- Lithium (Li): 670.8 nm
- Sodium (Na): 589.2 nm
- Rubidium (Rb): 780.0 nm
- Cesium (Cs): 455.5 nm
Now let's match these with the given options:
- A. Li (III): 670.8 nm
- B. Na (I): 589.2 nm
- C. Rb (IV): 780.0 nm
- D. Cs (II): 455.5 nm
Therefore, the correct answer is:
Option B
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)