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QJEEM24Cha36d: JEE Main 2024 Chemistry - Class 11 JEEM24Cha36d Solution: of gaseous hydrocarbon on combustion gives of and of water…

10 mL10 \mathrm{~mL} of gaseous hydrocarbon on combustion gives 40 mL40 \mathrm{~mL} of CO2( g)\mathrm{CO}_2(\mathrm{~g}) and 50 mL50 \mathrm{~mL} of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is _________ .

Step-by-Step Verified Solution

To solve this problem, we will use the fact that the volume ratio of gases in a reaction at the same conditions of temperature and pressure represents their mole ratio according to Avogadro's law. Thus, since the gas volumes given are at the same conditions, we can directly relate them to their stoichiometric coefficients in the balanced equation for combustion of a hydrocarbon.

The general equation for complete combustion of a hydrocarbon with a formula CxHy\mathrm{C}_x\mathrm{H}_y can be represented as:

CxHy+(x+y4)O2→xCO2+y2H2O

Given:

  • 10 mL10 \mathrm{~mL} of hydrocarbon ( CxHy\mathrm{C}_x\mathrm{H}_y )
  • 40 mL40 \mathrm{~mL} of CO2\mathrm{CO}_2
  • 50 mL50 \mathrm{~mL} of H2O\mathrm{H}_2\mathrm{O}

Since the volume ratios represent the mole ratios for gases, we can write the following ratios for the coefficients:

x1=40 mLCO210 mLCxHy=4

y2=50 mLH2O10 mLCxHy=5

From the first ratio, we see that:

x=4

This tells us that there are four carbon atoms in the hydrocarbon molecule.

From the second ratio, by multiplying both sides by 2, we get:

y=5×2=10

This means there are ten hydrogen atoms in the hydrocarbon molecule.

So, the total number of carbon and hydrogen atoms in the hydrocarbon is:

Total atoms=x+y=4+10=14

Therefore, the total number of carbon and hydrogen atoms in the hydrocarbon is 14.

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