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QJEEM24Cha09a: JEE Main 2024 Chemistry - Class 12 JEEM24Cha09a Solution: Time required for completion of of a First order reaction is…

Time required for completion of 99.9%99.9 \% of a First order reaction is ________ times of half life (t1/2)\left(t_{1 / 2}\right) of the reaction.

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t99.9%t1/2=2.303k(aa−x)2.303klog⁡2=log⁡(100100−99.9)log⁡2=log⁡103log⁡2=30.3=10\frac{\mathrm{t}_{99.9 \%}}{\mathrm{t}_{1 / 2}}=\frac{\frac{2.303}{\mathrm{k}}\left(\frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}}\right)}{\frac{2.303}{\mathrm{k}} \log 2}=\frac{\log \left(\frac{100}{100-99.9}\right)}{\log 2}=\frac{\log 10^3}{\log 2}=\frac{3}{0.3}=10

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