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QJEEM24Ch9627: JEE Main 2024 Chemistry - Class 12 JEEM24Ch9627 Solution: In the Claisen-Schmidt reaction to prepare 351   g of…

In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is _________ g. (Nearest integer)

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JEE Main 2024 (Online) 5th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 20 English Explanation

 mol of benzaldehyde required =1.5×2=3 mol mass =318 g

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