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QJEEM24Ch95b9: JEE Main 2024 Chemistry - Class 11 JEEM24Ch95b9 Solution: The enthalpy of formation of ethane from ethylene by addition…

The enthalpy of formation of ethane (C2H6)(\mathrm{C}_2 \mathrm{H}_6) from ethylene by addition of hydrogen where the bond-energies of C−H,C−C,C=C,H−H\mathrm{C}-\mathrm{H}, \mathrm{C}-\mathrm{C}, \mathrm{C}=\mathrm{C}, \mathrm{H}-\mathrm{H} are 414 kJ,347 kJ,615 kJ414 \mathrm{~kJ}, 347 \mathrm{~kJ}, 615 \mathrm{~kJ} and 435 kJ435 \mathrm{~kJ} respectively is −- __________ kJ\mathrm{kJ}

Step-by-Step Verified Solution

amp;C2H4+H2⟶C2H6amp;ΔHamp;=(615)+(435)−(347)−2(414)amp;=615+435−347−828amp;=−125 kJ\begin{aligned}& \mathrm{C}_2 \mathrm{H}_4+\mathrm{H}_2 \longrightarrow \mathrm{C}_2 \mathrm{H}_6 \\& \begin{aligned}\Delta \mathrm{H} & =(615)+(435)-(347)-2(414) \\& =615+435-347-828 \\& =-125 \mathrm{~kJ}\end{aligned}\end{aligned}

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