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QJEEM24Ch6d55: JEE Main 2024 Chemistry - Class 11 JEEM24Ch6d55 Solution: thick coating of silver is deposited on a plate of area. The…

0.05 cm0.05 \mathrm{~cm} thick coating of silver is deposited on a plate of 0.05 m20.05 \mathrm{~m}^2 area. The number of silver atoms deposited on plate are ________ ×1023\times 10^{23} . (At mass Ag=108, d=7.9 g cm−3\mathrm{Ag}=108, \mathrm{~d}=7.9 \mathrm{~g} \mathrm{~cm}^{-3} )

Step-by-Step Verified Solution

amp;amp; Volume of silver coating =0.05×0.05×10000amp;=25 cm3amp; Mass of silver deposited =25×7.9 gamp; Moles of silver atoms =25×7.9108amp; Number of silver atoms =25×7.9108×6.023×1023amp;=11.01×1023amp; Ans. 11\begin{aligned}&\begin{aligned}& \text { Volume of silver coating }=0.05 \times 0.05 \times 10000 \\\\& =25 \mathrm{~cm}^3 \\\\& \text { Mass of silver deposited }=25 \times 7.9 \mathrm{~g} \\\\& \text { Moles of silver atoms }=\frac{25 \times 7.9}{108} \\\\& \text { Number of silver atoms }=\frac{25 \times 7.9}{108} \times 6.023 \times 10^{23} \\\\& =11.01 \times 10^{23}\end{aligned}\\\\&\text { Ans. } 11\end{aligned}

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