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QJEEM24Ch6070: JEE Main 2024 Chemistry - Class 12 JEEM24Ch6070 Solution: Given below are two statements : Statement I : The rate law for …

Given below are two statements :

Statement I : The rate law for the reaction A+B→CA+B \rightarrow C is rate (r)=k[A]2[B](r)=k[A]^2[B] . When the concentration of both A\mathrm{A} and B\mathrm{B} is doubled, the reaction rate is increased " xx " times.

Statement II : JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 22 English

The figure is showing "the variation in concentration against time plot" for a " yy " order reaction.

The Value of x+yx+y is __________.

Step-by-Step Verified Solution

amp;x=8,y=0amp;r2r1=(CA2CA1)2(CB2CB1)amp;r2r1=(2CA1CA1)2(2CB1CB1)amp;r2=8r1amp;x=8\begin{aligned}& x=8, y=0 \\& \frac{r_2}{r_1}=\left(\frac{C_{\mathrm{A}_2}}{C_{\mathrm{A}_1}}\right)^2\left(\frac{\mathrm{C}_{\mathrm{B}_2}}{\mathrm{C}_{\mathrm{B}_1}}\right) \\& \frac{\mathrm{r}_2}{\mathrm{r}_1}=\left(\frac{2 \mathrm{C}_{\mathrm{A}_1}}{\mathrm{C}_{\mathrm{A}_1}}\right)^2\left(\frac{2 \mathrm{C}_{\mathrm{B}_1}}{\mathrm{C}_{\mathrm{B}_1}}\right) \\& \mathrm{r}_2=8 \mathrm{r}_1 \\& x=8\end{aligned}

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 22 English Explanation

amp;⇒ Zero order amp;y=0\begin{aligned}& \Rightarrow \text { Zero order } \\& y=0\end{aligned}

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