Verified Solution • 2025–26 Session moderate

QJEEM24Ch4f2e: JEE Main 2024 Chemistry - Class 12 JEEM24Ch4f2e Solution: When ' x ' × 10 − 2   mL methanol (molar mass = 32  …

When 'x' ×10−2 mL methanol (molar mass =32 g' density =0.792 g/cm3) is added to 100 mL. water (density =1 g/cm3), the following diagram is obtained.

JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Solutions Question 10 English

x= ________ (nearest integer).

[Given : Molal freezing point depression constant of water at 273.15 K is 1.86 K kg mol−1]

Step-by-Step Verified Solution

ΔTf=2.5∘CΔTf=i×kf×m2.5=1×1.86×nB0.1nB=2.5×0.11.86=0.1344 mol mass of methanol =0.1344×32=4.3 gd=mvv=mdv=4.30.792 mL=5.43 mL=543×10−2 mLx=543

Related Learning Resources & Exam Preparation