QJEEM24Ch4b1f: JEE Main 2024 Chemistry - Class 12 JEEM24Ch4b1f Solution: r = k [ A ] for a reaction, 50 % of A is decomposed in 120…

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QJEEM24Ch4b1f: JEE Main 2024 Chemistry - Class 12 JEEM24Ch4b1f Solution: r = k [ A ] for a reaction, 50 % of A is decomposed in 120…

$r = k [A]$ for a reaction, $50 %$ of $A$ is decomposed in 120 minutes. The time taken for $90 %$ decomposition of $A$ is _________ minutes.

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Accepted Answer

$r = k [A]$

So, order of reaction $= 1$

$t_{1 / 2} = 120 \min$

For $90 %$ completion of reaction

$\begin{aligned} \Rightarrow k = \frac{2.303}{t} \log (\frac{a}{a - x}) \\ \Rightarrow \frac{0.693}{t_{1 / 2}} = \frac{2.303}{t} \log \frac{100}{10} \\ ∴ t = 399 \min . \end{aligned}$

QJEEM24Ch4b1f: JEE Main 2024 Chemistry - Class 12 JEEM24Ch4b1f Solution: r = k [ A ] for a reaction, 50 % of A is decomposed in 120…

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