Verified Solution • 2025–26 Session moderate

QJEEM24Ch45c6: JEE Main 2024 Chemistry - Class 11 JEEM24Ch45c6 Solution: Given below are two statements : Statement I : The metallic…

Given below are two statements :

Statement I : The metallic radius of Na\mathrm{Na} is 1.86 A∘1.86 \mathrm{~A}^{\circ} and the ionic radius of Na+\mathrm{Na}^{+} is lesser than 1.86 A∘1.86 \mathrm{~A}^{\circ}

Statement II : Ions are always smaller in size than the corresponding elements.

In the light of the above statements, choose the correct answer from the options given below :

Multiple Choice Options

  • A Both Statement I and Statement II are true
  • B Statement I is incorrect but Statement II is true
  • C Both Statement I and Statement II are false
  • D Statement I is correct but Statement II is false

Step-by-Step Verified Solution

To determine the correctness of the given statements, let's analyze each one individually based on atomic and ionic radii concepts.


Statement I:

The metallic radius of Na\mathrm{Na} is 1.86 A˚1.86\, \text{Å} and the ionic radius of Na+\mathrm{Na}^+ is lesser than 1.86 A˚1.86\, \text{Å} .

Analysis:

Metallic Radius of Sodium ( Na\mathrm{Na} ):

Sodium is a metal, and its metallic radius is indeed approximately 1.86 A˚1.86\, \text{Å} .

The metallic radius refers to half the distance between the nuclei of two adjacent atoms in a metallic lattice.

Ionic Radius of Sodium Ion ( Na+\mathrm{Na}^+ ):

When sodium loses an electron to form Na+\mathrm{Na}^+ , it loses its outermost electron shell (the 3s orbital).

This results in a significant decrease in size due to:

Decrease in Electron-Electron Repulsion: Fewer electrons mean less repulsion among them.

Unchanged Nuclear Charge: The number of protons remains the same, so the effective nuclear charge per electron increases, pulling the remaining electrons closer to the nucleus.

The ionic radius of Na+\mathrm{Na}^+ is approximately 0.95 A˚0.95\, \text{Å} , which is significantly smaller than 1.86 A˚1.86\, \text{Å} .

Conclusion:

Statement I is correct.


Statement II:

Ions are always smaller in size than the corresponding elements.

Analysis:

General Trends:

Cations ( Positive Ions\text{Positive Ions} ):

Formed by the loss of one or more electrons.

Result: Cations are smaller than their parent atoms due to loss of electron(s) and decreased electron-electron repulsion.

Example: Na→Na+\mathrm{Na} \rightarrow \mathrm{Na}^+ (size decreases).

Anions ( Negative Ions\text{Negative Ions} ):

Formed by the gain of one or more electrons.

Result: Anions are larger than their parent atoms due to added electron(s) and increased electron-electron repulsion.

Example: Cl→Cl−\mathrm{Cl} \rightarrow \mathrm{Cl}^- (size increases).

Exceptions to Statement II:

Since anions are larger than their corresponding neutral atoms, the statement that "ions are always smaller in size than the corresponding elements" is incorrect.

Conclusion:

Statement II is false.


Final Answer:

Statement I is correct but Statement II is false.

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